娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方k d5HgCK
r!`0B"_HsiZ
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:id?vW hV5V|K
3的12次方=531441 [/quote]
q T1z!DNsRsB )u4p;~H&p9kk
都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:
v5Yp-NK zvw~ 1的32次方0a})m%zE"@/j(V

QH C i_"D!B)\6MF j [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]h,K$S/G8M8zaJ

`2?(c2[~)W
8q R:NF y6Nn'v%_U8DW :(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h+eai2ht(L h'\9l
=13BFEFA65ABB83! hF$hZ8X&l v
=5559060566555523!? Y4Q4\1~1r1Wo
=您所要求的操作可能要花一段很長時間才能完成。slIJcY(EK
=操作己取消"i w5t|aZ(r
u.B.O Kss6q
[[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:
-o+m,AzM ^ ~ J v9A6YY fLM
L:~ o&B}zFg^c
5A J#a;V)aT*XE
:(咁係一喎                 :giveup: [/quote]
,hz2p\9Mt
C%R{,b(`e3u-E2b 哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

頁: [1]

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