娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方:K+`$S+P:H+b*|

a(bec8u1Qk0o [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:N7fq(Q0H1|p
3的12次方=531441 [/quote]
2L {'lT w/Q&P4{C D _uzK knfi
都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:^z.tB+{2}JI;SG
1的32次方
8I{Q,VG4IX E%K4Q#{&D H
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]
)~2^h3`:zZ&V7^j a{{ T5O.QrA
g-l;?s#tM%r
:(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h0z_ kAcVN)s
=13BFEFA65ABB83! h%C9mC+OW
=5559060566555523!&o*B6{2@5|7Hh
=您所要求的操作可能要花一段很長時間才能完成。
&q/t'l#~{0s[s =操作己取消
0|&G W;P\
T1pB4EA-l[ [[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:
TteI4q LZ/cN"n
(g-ZJ;\?:I8V;C (UFC:c6y8DJ7]!M

6_4c5SiD-x#h :(咁係一喎                 :giveup: [/quote]
? V*h}#`LY/] J(~ /\r9YJ \%t7M9L+q
哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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