seafireson2

如果北極有個洞真穿南極, 6 {5 K8 O$ |5 a" z, N
您跌入去,2 v" h: U; p& B  W0 t
您會去到達南極~4 d, `. _& X& \+ j, o  D
但到達南極後會吸回北極~~~$ T9 }/ f$ Y6 x- S# }4 b' M' H; @
到北極後又會吸回南極................
+ c' {- u0 Q% B( f' c) O即係好像彈簧0甘~~~' d) @6 i1 c" C# E- ^8 B
(假設地球質量是平衡分佈)- E, Y8 g9 j1 U5 Z+ I
(answer 來自我的預科物理ar sir)- O1 @. v1 D. K, X6 {( ?# k5 X

& y3 ?. g/ }6 `$ e8 ^! J4 r. l! p事實上,地球質量是唔平衡分佈,$ z/ f# D- w, M& s& ?9 m' r& p1 r
so 一次反彈的力量會比一次少,+ F6 x/ P! z0 T
then 一次反彈的距離會比一次少5 w+ \! p! \2 O3 L% h
最後您會停在地心......: I, [! U) u: G6 a/ o: z/ l7 R6 k
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[ Last edited by seafireson2 on 2006-5-8 at 11:05 PM ]

seafireson2

Originally posted by gaye at 2006-5-8 11:35 PM:$ e* X3 D. S& n+ {; x2 R

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! J. i' m3 L. k% Y0 L8 G" l但假如我唔係 North Pole jump 落...

- P$ J9 s0 Z% M9 ^. O/ x+ k2 |3 v....................==""3 `& m2 [/ V3 C1 I' Z& G- C. q9 \& m+ W
爬上去定爬落去係相對...............7 E* ], X: z$ ]% H; |, q! X! f
個方向係由您set......& ?( P- D2 h6 m5 t, K6 t, ^
您定義north pole 係上面,0甘咪爬落law...6 t: E. U9 v1 I3 Z; R9 E9 w
您定義south pole 係上面,0甘咪爬上law...
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" S) q; e3 |3 A) w; Dhowever,點解唔simple d 呢........3 b8 m' {+ y3 Y& M+ u
由地心去south pole,: a5 G: U, J$ @
0甘咪ok law..........

seafireson2

Originally posted by 機密 at 2006-5-9 12:10 AM:
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無乜可能，除了極熱之外，還要頂得住地心的高壓！ 未到對面你都變左屎餅啦！ 瓜！

' p0 X3 Z4 `3 C9 y6 \, P都話明"假設"ar!!!!!!假設唔一定要正確ga.............

seafireson2

Originally posted by FishyR at 2006-5-9 05:09 PM:
, ?# F+ O' Y8 @我結論係去唔到最中心, 而喺地心同地面之間停下來. 喺個點係無地心吸力, 因地面質量對我所做成o既萬有引力, 同地心質量對我所做成o既萬有引力喺對等.

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其實係去到地心,南北半球ge地心吸力先相等同抵消~so地心ga引力係0~~~~
/ z5 L% V6 }, C3 w但您之前有加速,即您本身有speed~0甘您會直去,但去南半球時又受引力,會減speed,最後係南半球表面stop~~~