| TriTri | A-Math 加分題 |

Triangel

第一個答中有獎
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$ }8 ~4 @8 S3 V( u(x - a) = x - a
- R5 Q. U8 @0 Y(x - a) (x - b) = x^2 – ax – bx + ab2 y( C: \6 |& e% ~! W& r
(x - a) (x - b) (x – c) =  x^3 – ax^2 – bx^2 – cx^2 + abx + acx + bcx - abc/ J* [0 G+ x$ Z% a
(x - a) (x - b) (x – c) (x - d) = x^4 – ax^3 – bx^3 – cx^3 – abx^2……………….. +abcd: S# V9 D0 ~$ x" D6 K9 j9 T) K
如此種推，
" t' [/ b9 ?  E( j2 D( r* q: T* {(x-a) (x-b) (x-c) (x-d) (x-e)……..(x-z) = ???
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2 d2 ]) j1 \( A3 L3 d: I3 U[ Last edited by Triangel on 2007-4-18 at 01:52 PM ]

Triangel

Originally posted by 大大 at 2007-4-18 01:41 PM:) F5 @; f6 @0 G: C0 p) S7 H
咁難既=.="0 @8 ^( u& @5 a0 E! w' [4 Y3 j$ ?
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[ Last edited by 大大 on 2007-4-18 at 01:52 PM ]

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Thanks! 更正啦

Triangel

Originally posted by littlenic at 2007-4-18 01:54 PM:
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(x-x)= 0 ，所以答案係0，is it?

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) j, \: y4 G, V9 o) EBingo~