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發表於 2006-5-9 12:03 AM
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Originally posted by gaye at 2006-5-8 11:35 PM:
1 X$ J$ M ^1 t" y% [ I4 a9 |$ i# \
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3 a& S6 g2 N& _3 J1 `但假如我唔係 North Pole jump 落... # o: R- {- i7 j" e3 \( R' f
$ p' l3 x# [2 o, E4 a# z5 i6 Q
5 v4 z8 k* d7 i- a0 i" M. q* @. }. r7 v2 L' s3 b
咁我諗要睇你點define上同落, F+ u$ m0 X4 q7 p
! ^7 z- z8 U" j1 X6 e
好似好廢...! l4 R* Z+ j, I2 y
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& ]. J& @* Q2 M7 c5 L4 P, Z
- ]4 N! t4 i; s; N即係話如果你設由north -> south為落4 N" \) b4 f+ e0 i0 Z
由core去到south, 對north而言依然叫落4 n/ a: M( K7 I1 i6 e: l1 z( {
vice versa
) g. f2 z ]& h9 z/ n& h4 i7 _' T' v6 g: o' o% O
/ }; c' D+ u3 J
反而有樣野你要bear in mind ge係
& C( U" ~( F2 {% e! d+ u由core出發, 要input energy |
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