|
 
- 帖子
- 189
- 精華
- 0
- 威望
- 76
- 魅力
- 0
- 讚好
- 0
- 性別
- 男
|
8#
發表於 2006-5-9 12:03 AM
| 只看該作者
Originally posted by gaye at 2006-5-8 11:35 PM:3 K5 H$ H, _: ?/ p3 K, `( n
/ N; }) T, i( c5 M% K0 C# Q( @" d
' {$ C+ c' h q3 y. m; D1 s( t0 N1 W
但假如我唔係 North Pole jump 落... - L' ^" G. B. n' P: s& d8 c) T4 @( p; x! z9 ^2 e3 e
7 X+ ?0 w2 b5 @, @: N4 |8 @4 k. O. I/ }6 I- F; j9 {+ `
咁我諗要睇你點define上同落+ m0 m" Y) T5 S* n( P
k* \; @7 Z5 H好似好廢...4 J( k* H, f& B0 D5 l
7 i) t8 x4 e3 \, }' e$ O5 ?0 Z; O# b
! X- @* [: [7 Q2 K3 s# u: ]5 y9 b
即係話如果你設由north -> south為落
1 U7 T: o% z2 A; G/ h$ Q/ o由core去到south, 對north而言依然叫落
/ I( e) s! u3 Qvice versa( t2 ?; E# h9 u% e5 r
; u1 t2 d: p; h! `+ X" \
* W; Y9 Q3 u% h$ x, E- Y# x5 z. U
反而有樣野你要bear in mind ge係2 d& \# x, }! R8 \; ^
由core出發, 要input energy |
|