| TriTri | A-Math 加分題 |

Triangel

第一個答中有獎
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" _8 }- R. ~# S0 q(x - a) = x - a7 z& C- Z' k; v8 g# p$ J  y2 K4 n
(x - a) (x - b) = x^2 – ax – bx + ab
( Q6 ~  A( c. Y6 d(x - a) (x - b) (x – c) =  x^3 – ax^2 – bx^2 – cx^2 + abx + acx + bcx - abc
: C( n. e! C4 m" y' g(x - a) (x - b) (x – c) (x - d) = x^4 – ax^3 – bx^3 – cx^3 – abx^2……………….. +abcd; [' G: {3 J7 M8 ~2 T6 y1 K4 [" h
如此種推，
; c/ M% {+ Q3 q: ]8 W; C$ J' _(x-a) (x-b) (x-c) (x-d) (x-e)……..(x-z) = ???
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5 V7 _: f- J* e[ Last edited by Triangel on 2007-4-18 at 01:52 PM ]

Triangel

Originally posted by 大大 at 2007-4-18 01:41 PM:8 K2 \$ C0 M* v( y8 }2 s! t
咁難既=.="' ?, C+ X% k5 l0 c# I; ]9 i7 `
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[ Last edited by 大大 on 2007-4-18 at 01:52 PM ]

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4 B  d2 K- u! {* W8 h; t* E/ WThanks! 更正啦

Triangel

Originally posted by littlenic at 2007-4-18 01:54 PM:9 _0 e) v! |" I& h! `+ h+ {& y5 d5 Q
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+ v) G- X" y  T/ s) \(x-x)= 0 ，所以答案係0，is it?

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, v& q$ F& q$ ?+ O. oBingo~